2(3x-4)^2-16=32

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Solution for 2(3x-4)^2-16=32 equation: 



2(3x-4)^2-16=32

We move all terms to the left:

2(3x-4)^2-16-(32)=0

We add all the numbers together, and all the variables

2(3x-4)^2-48=0

We move all terms containing x to the left, all other terms to the right

2(3x-4)^2=48

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